Feature: Add DebuggerInfo to ApplicationModel
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4ecbe8c709
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@ -2,11 +2,14 @@
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// Licensed under the Apache License, Version 2.0. See License.txt in the project root for license information.
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using System.Collections.Generic;
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using System.Diagnostics;
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using System.Linq;
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using System.Reflection;
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namespace Microsoft.AspNet.Mvc.ApplicationModels
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{
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[DebuggerDisplay("Name={ActionName}({Methods()}), Type={Controller.ControllerType.Name}," +
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" Route: {AttributeRouteModel?.Template}, Filters: {Filters.Count}")]
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public class ActionModel
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{
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public ActionModel([NotNull] MethodInfo actionMethod,
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@ -91,5 +94,15 @@ namespace Microsoft.AspNet.Mvc.ApplicationModels
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/// <see cref="ApplicationModel.Properties"/> and <see cref="ControllerModel.Properties"/>.
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/// </remarks>
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public IDictionary<object, object> Properties { get; }
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private string Methods()
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{
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if (HttpMethods.Count == 0)
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{
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return "All";
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}
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return string.Join(", ", HttpMethods);
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}
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}
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}
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@ -2,9 +2,11 @@
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// Licensed under the Apache License, Version 2.0. See License.txt in the project root for license information.
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using System.Collections.Generic;
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using System.Diagnostics;
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namespace Microsoft.AspNet.Mvc.ApplicationModels
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{
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[DebuggerDisplay("ApplicationModel: Controllers: {Controllers.Count}, Filters: {Filters.Count}")]
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public class ApplicationModel
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{
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public ApplicationModel()
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@ -2,11 +2,14 @@
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// Licensed under the Apache License, Version 2.0. See License.txt in the project root for license information.
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using System.Collections.Generic;
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using System.Diagnostics;
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using System.Linq;
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using System.Reflection;
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namespace Microsoft.AspNet.Mvc.ApplicationModels
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{
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[DebuggerDisplay("Name={ControllerName}, Type={ControllerType.Name}," +
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" Routes: {AttributeRoutes.Count}, Filters: {Filters.Count}")]
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public class ControllerModel
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{
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public ControllerModel([NotNull] TypeInfo controllerType,
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@ -2,11 +2,13 @@
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// Licensed under the Apache License, Version 2.0. See License.txt in the project root for license information.
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using System.Collections.Generic;
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using System.Diagnostics;
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using System.Reflection;
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using Microsoft.AspNet.Mvc.ModelBinding;
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namespace Microsoft.AspNet.Mvc.ApplicationModels
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{
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[DebuggerDisplay("ParameterModel: Name={ParameterName}")]
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public class ParameterModel
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{
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public ParameterModel([NotNull] ParameterInfo parameterInfo,
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